Phenobarbital PML example

This example illustrates simple PK modeling for a one-compartment model with Cl (clearance) and V (volume) parameterization, and multiple doses per subject.

Data

The subject data are contained in an ASCII file (*.dat). The headers and the first subject data read as follows:

pheno.dat 
## xid time dose wt apgr yobs
1 0.0 25.0 1.4 7 .
1 2.0 . 1.4 7 17.3
1 12.5 3.5 1.4 7 .
1 24.5 3.5 1.4 7 .
1 37.0 3.5 1.4 7 .
1 48.0 3.5 1.4 7 .
1 60.5 3.5 1.4 7 .
1 72.5 3.5 1.4 7 .
1 85.3 3.5 1.4 7 .
1 96.5 3.5 1.4 7 .
1 108.5 3.5 1.4 7 .
1 112.5 . 1.4 7 31.0

Column mappings

The ASCII file containing column mappings reads as follows.

   colspheno.txt 
id(xid)
time(time)
dose(a <- dose)
covr(wt <- wt)
obs(cObs <- yobs)

The model

The PML model file reads as follows.

phenophxexam.mdl 
# One compartment model with IV bolus dosing
# Cl, V parameterization with differential equation
# formulation
Pheno(){
dosepoint(a)
covariate(wt) #wt is a covariate for Cl and V
deriv(a=-a*Cl/V)
c=a/V
fixef(
tvCl=c(0, 0.0001,)
wtCl=c(0, 0.005,)
tvV=c(0, 0.1,)
wtV=c(0, 1,)
)
ranef(
diag(nCl, nV)=c(0.1, 0.1,)
)
stparm(
Cl=(tvCl+wtCl*wt)*exp(nCl)
V=(tvV+wtV*wt)*exp(nV)
)
#NONMEM initial estimate for sigma variance is 10
#Phoenix initial estimate represents a standard deviation
#rather than a variance, so the equivalent initial estimate is
#eps1=sqrt(10)=3.16
# error(eps1=3.16)
# observe(cObs=c+eps1)
}

NONMEM control file

The equivalent model, written as a NONMEM control file (*.ctl), would read as follows.

  $PROBLEM PHENOBARB SIMPLE MODEL
$INPUT ID TIME AMT WGT APGR DV
$DATA pheno.dat
$SUBR ADVAN6
$MODEL COMP=(CENTRAL,DEFOBS,NOOFF)
$PK
TVCL=THETA(1)+WGT*THETA(2)
TVV=THETA(3)+WGT*THETA(4)
CL=TVCL*EXP(ETA(1))
V=TVV*EXP(ETA(2))
S1=V
$THETA(0, 0.0001,)(0, 0.005,)(0, .1,)(0, 1,)
$OMEGA .1 .1
$DES
DADT(1)=-CL/V*A(1)
$ERROR
Y=F+EPS(1)
$SIGMA 10
$ESTIMATION METHOD=1 PRINT=5 POSTHOC

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